Winner of Oceania youth championship in Guam to advance to U-18 Baseball World Cup 2019
14/01/2019 1 Minute Read

Winner of Oceania youth championship in Guam to advance to U-18 Baseball World Cup 2019

The top youth team in Oceania will qualify for the WBSC U-18 Baseball World Cup 2019. American Samoa, Guam, Australia, New Zealand, and Palau will battle from 22-27 January at the Paseo Stadium in Agana, Guam

The U-18 Baseball Confederation of Oceania (BCO) Championship will open on Tuesday, 22 January, at Paseo Stadium in Agana, Guam. The final is scheduled for Sunday, 27 January. Five nations will battle for Oceania’s top youth crown, including American Samoa, Guam, Australia, New Zealand and Palau.

The continental champion will become the 11th of 12 teams to qualify for the WBSC U-18 Baseball World Cup 2019, which will be staged at the end of the summer in Gijang, Korea.

The 14-game tournament will begin with a round robin, with the top four teams advancing to a page-system playoff.

The top two from the round robin will advance to the first semifinal, with the winner advancing to the championship game and the loser playing against the winner of the knockout game between the third and fourth seeds.

The loser of second semifinal will be knocked out with a bronze medal, while the winner will advance to the championship game.

U-18 Oceania Baseball Championship – Schedule

22 January
7 pm Guam-Palau

23 January
11 am American Samoa-Palau
3 pm American Samoa-Australia
7 pm New Zealand-Guam

24 January
11 am New Zealand-Palau
3 pm New Zealand-American Samoa
7 pm Australia-Guam

25 January
11 am Australia-New Zealand
3 pm Palau-Australia
7 pm Guam-American Samoa

26 January-semifinals
1 pm No 1 seed-No 2 seed (a)
6 pm No 3 seed-No 4 seed (b)

27 January-medal games
12 pm loser (a)-winner (b)-bronze medal game (c)
5 pm winner (a)-winner (c)-championship game

local time in Guam is CEST + 9 and US Eastern + 15

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Qualified from the Americas

Qualified from Asia